AntarcticPilot
Well-known member
Astro in a nut-shell!
At any particular moment, any celestial body (Sun, Moon, planet, star) is directly over a specific point (the nadir point) on the Earth's surface. If you know this point (which requires an ephemeris and time), and measure the elevation of the object using a sextant, in principle you know that you're on a circle centred on that point, whose radius is 90 - the measured elevation in degrees. You can use that circle (which because you know roughly where you are from DR, you can regard as a line perpendicular to the direction of the nadir point) as a position line in exactly the same way as any other position line.
Of course, there are a lot of other things to take into account, such as the effects of your height above sea-level, atmospheric refraction and (for the Moon) parallax errors, but in principle it really is as simple as that. Of course, the mathematics of spherical trigonometry is a bit tricky, but people have kindly worked out rule based methods of side-stepping that bit.
At any particular moment, any celestial body (Sun, Moon, planet, star) is directly over a specific point (the nadir point) on the Earth's surface. If you know this point (which requires an ephemeris and time), and measure the elevation of the object using a sextant, in principle you know that you're on a circle centred on that point, whose radius is 90 - the measured elevation in degrees. You can use that circle (which because you know roughly where you are from DR, you can regard as a line perpendicular to the direction of the nadir point) as a position line in exactly the same way as any other position line.
Of course, there are a lot of other things to take into account, such as the effects of your height above sea-level, atmospheric refraction and (for the Moon) parallax errors, but in principle it really is as simple as that. Of course, the mathematics of spherical trigonometry is a bit tricky, but people have kindly worked out rule based methods of side-stepping that bit.