wipe_out
Well-Known Member
Just curious about the range of a hand held VHF at 1w power.. If the 5w power is supposed to reach 5 miles line of sight then does that translate to 1w being roughly 1 mile line of sight?
But that was through a vacuum.BTW forget Apollo - I think Voyager's radio was only about 20W and that could transmit data 12,000,000,000 miles![]()
From a purely numerical point of view I would expect it to be nearer to a square rule (i.e. much less than 1 mile) but that is so simplistic as to be pretty much useless. With clear line of sight I would expect about 1 mile but anything in the way and it could drop to a couple of hundred yards.
BTW forget Apollo - I think Voyager's radio was only about 20W and that could transmit data 12,000,000,000 miles![]()
If it is a simple as the square rule, it would be more than a mile - actually more than two.
just do the maths - the square root of five
That doesn't seem correct. It's an inverse square law, so decreasing the transmitting power by a factor of 5 will reduce range by a factor of 2.23 at which the reception power is the same, other things being equal.Would you like to think about that one again
If the radio wave propagated in all directions then the distance would be proportional to the square of the power - so 1W would travel 1/25th of the distance of 5W.
In free space.Would you like to think about that one again
If the radio wave propagated in all directions then the distance would be proportional to the square of the power - so 1W would travel 1/25th of the distance of 5W. In fact even for handhelds with very small antennae the propagation is nothing like omni-directional so they can do much better than that, but certainly not linear.
Oops yes I seem to be standing on my headThat doesn't seem correct. It's an inverse square law, so decreasing the transmitting power by a factor of 5 will reduce range by a factor of 2.23 at which the reception power is the same, other things being equal.
As Davidej said.
But that was through a vacuum.