phlip
New Member
Not quite right: the second moment of area is proportional to the _stiffness_ (for the usual "elastic plane-sections-remain-plane" scenario if we're going to be super precise - sorry!), not the strength.A tube does not have a higher bending strength than a solid cylinder of the same diameter. The strength of each depends on the second moment of inertia along the Z axis. The second moment of inertia of a solid cylinder is greater than the tube of the same diameter because the cylinder includes all the central part of the solid that is not there in the tube, apart from an infinitely thin strip at the centre of the cylinder that contributes nothing to the bending strength.
You calculate the second moment of inertia of a cylinder in the Z direction like this...
View attachment 175509
For a tube you do the calculation twice - for the outer radius and then the inner radius and subtract the inner result from the outer result, or combine the subtraction into the equation like this...
View attachment 175511
As you can see it depends on the 4th powers of the radius, so for an identical mass of material a tube gets much stronger than a solid cylinder quickly. For a given mass per length the strongest you could make it would be a tube with the mathematical limit of an infinitely big radius and a zero thickness wall, but fitting it in your hull may be tricksome.
The strength (resistance to bending moment) is proportional to r (or D) cubed - but there's more than one strength - are we looking for the bending moment that causes any of the section to yield, or the moment that is achieved when the whole section is plasticised - e.g. half of the circle is yielding in compression, and half of it in tension.