lw395
Well-Known Member
Doesn't it also need direction of travel of the boat?
No.
Forget your land frame of reference.
consider a boat with an apparent wind 30 degrees off the bow.
The apparent windspeed is 15 knots
The boat speed is 5 knots
You can draw that in a boat speed+ true wind= apparent wind triangle
The component of the apparent wind at right angles to the boat is 15 sin30 knots
The component of the true wind in that direction is the same. 7.5knots
The component of the apparent wind parallel to the boat is 15 cos30 or 13 knots
The component of the true wind parallel to the boat is 13-5 = 8 knots.
The true wind speed is sqrt (8^2 + 7.5^2) = 11 knots
The true wind angle is arctan (7.5/8) =43degrees off the bow.
