rustybarge
Well-Known Member
Hi all,
At last The dark arts of sailing are revealed 'in another place' about the 'real world' speed of performance yachts.
To sum up: an electric trolling outboard of 2 hp would propel a heavy mobo at a faster speed into the wind, than a high performance sailboat which can only make about 2 kts 'speed over the ground' directly to it's destination by the time you take into account the tacking zigzags.
And that's on a good day!!!
This is how they calculate their upwind speed against the wind:
http://www.ybw.com/forums/showthrea...to-windward-how-much-more-time-to-allow/page2
30 hrs to do 60 nm at 2kts with the sails, or 15 hrs at 4kts to motor with the saildrive for the same 60 mn.....
No wonder Raggies are so bolshie ......2kts

Can you believe it: 2 kts.............
At last The dark arts of sailing are revealed 'in another place' about the 'real world' speed of performance yachts.
To sum up: an electric trolling outboard of 2 hp would propel a heavy mobo at a faster speed into the wind, than a high performance sailboat which can only make about 2 kts 'speed over the ground' directly to it's destination by the time you take into account the tacking zigzags.
This is how they calculate their upwind speed against the wind:
.
Originally Posted by Seven Spades
Simple boat speed x COS (bearing difference) Bearing difference is the difference in angle between where you are going and where you want to go. So for example if your destination is way 270 degrees but you can only sail at 310 degrees and you boat speed is 6knts then your effective speed is down to 6 x COS (40) = 6 x 0.766 =4.6knts you can work this out on any mobile phone.
That's useful, thank you. So I'll apply that to my figures above (ignoring lee-bowing the cross-tides):
Sailing at 4.0kts at a bearing difference of 60 deg (50 deg maintainable plus 10 deg leeway):
4 x COS (60) = 4 x 0.5 = 2kts, therefore 30 hours to cross 60NM to Cherbourg.
2. Motorsailing at 5.5 kts at a BD of at least 45 deg (35 deg to wind plus 10 leeway):
5.5 x COS (45) = 5.5 x 0.7 = 4kts appx, therefore 15 unpleasantly wet, heeled and noisy hours to cross
No brainer, then...
http://www.ybw.com/forums/showthrea...to-windward-how-much-more-time-to-allow/page2
30 hrs to do 60 nm at 2kts with the sails, or 15 hrs at 4kts to motor with the saildrive for the same 60 mn.....
No wonder Raggies are so bolshie ......2kts
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