MM5AHO
Well-Known Member
Here's a simpler method that Alain F's
WIND FORCES
The main force which is experienced by a yacht at anchor comes from wind resistance. It is proportional to the wind speed squared and to the frontal area presented by the yacht. Broadly speaking the frontal area will be proportional to the square of the length. Provided snatching does not occur, the maximum force on the anchor cable is given by the approximate formula:
Maximum force in kg = (yacht length in metres)2 x (wind speed in knots)2/500
F(wind) = L2xV2/500 (units kilograms,metres and knots) Formula 2
Force is measured in kilograms; wind speed in knots, yacht length in metres.
So with a 10 metre yacht anchored in a 30 knot wind, the maximum force on the anchor cable is expected to be about 180 kg if the chain is not tensioned beyond the borderline state. (borderline state is when its about 2 links for fully tensioned with no catenerary) The force will be much larger if snatching occurs.
WIND FORCES
The main force which is experienced by a yacht at anchor comes from wind resistance. It is proportional to the wind speed squared and to the frontal area presented by the yacht. Broadly speaking the frontal area will be proportional to the square of the length. Provided snatching does not occur, the maximum force on the anchor cable is given by the approximate formula:
Maximum force in kg = (yacht length in metres)2 x (wind speed in knots)2/500
F(wind) = L2xV2/500 (units kilograms,metres and knots) Formula 2
Force is measured in kilograms; wind speed in knots, yacht length in metres.
So with a 10 metre yacht anchored in a 30 knot wind, the maximum force on the anchor cable is expected to be about 180 kg if the chain is not tensioned beyond the borderline state. (borderline state is when its about 2 links for fully tensioned with no catenerary) The force will be much larger if snatching occurs.