cpedw
Well-Known Member
The voltage when current is flowing (e.g. fridge on) is reduced because of the battery's internal resistance. From your numbers, the 40W fridge is taking a bit over 3A at 12V so the 0.3V drop measured at the battery is due to 0.3/3 = about 0.1 ohm internal resistance."I would expect a rested ( ie no load for 24 hours ) volts of about 12 .2 when 50% discharged"
Does it matter if a battery drops below 12.2 when actually in use, say running a fridge?
Even from 12.7 mine drop to 12.4 when the 40w fridge is on which gives a very low "range of use" :
12.7 = 12.4 fridge on
12.6 = 12.3
12.5 = 12.2
12.4 resting =12.1 fridge on = > 50% discharged?
It's hard enough to infer SOC from rested battery voltage. It's next to impossible when the battery is delivering current.
Derek