FullCircle
Well-Known Member
It seems we no longer rule the waves......
And who can explain why the 0.18m gets missed off in 1995?
And who can explain why the 0.18m gets missed off in 1995?
the increase in distance between Europe and the Americas in the 20th century ? As redefined by new satellitic measurements in 1995 ?
The Nautical Mile
In 1929 it was defined as 1852 meters
The Imperial NM is 6080 feet which is 1853.184 metersand was rounded down (presumably in 1995) to 1853 meters
(Wikipedia is my friend)
So where is the UK datum taken for a 6080ft NM?
I'll do my Alan Davis QI impression.....So where is the UK datum taken for a 6080ft NM?
I'll do my Alan Davis QI impression.....
Greenwich?
I did learn something.... Aparently WGS84 is based on the Paris meridian because the Americans couldn't be ar5ed to change all their charts - despite it being agreed in 1884 by 25 countries (including USA) that it would be Greenwich.
Is that one minute of arc along any great circle? If my schoolboy knowledge is accurate the longest great circle is around the equator and the shortest between the poles (presumably all meridians are roughly equal in length?) If the nautical mile was based on a datum measured somewhere in Great Britain this somewhat limits the range of circles. The resultant great circle will fall in a range from one aligned true north/south to one inclined no more than 39 degrees from north/south. Somebody, I am sure, can do the maths.
To accurately determine one minute to establish a datum would presumably require some clever celestial mathematics, with a flat horizon and an easily observed extraterrestrial object - rather rules out Greenwich.
The metre I seem to recall was intended to be a 40 000 000th of the great circle along the Paris meridian but they couldn't determine this accurately and the datum (a metal bar) is therefore wrong.
40 000 000 divided by 21 600 (number of minutes in a circle) = 1851.85
ps I note in passing that the average of 6108 and 6046 is 6077, not 6080. And 6076.6 is a damned sight closer to the average. Oh sorry, I am not to concern myself with that.
Ah but the English Channel is not halfway between the equator and the North Pole. In practice the rate of change in the length of 1' arc between pole and equator is probably not linear, but if we take 51 deg N then:
1' arc = 6046+((6108-6046)*(51/90))=6081.13 ft.
at 49 deg N it would be:
1' arc = 6046+((6108-6046)*(49/90))=6079.76 ft.
but that will include the projection scale factor in the calculated distance and it's not applicable in this situation!i would double check that new Furuno if i were you![]()