VicS
Well-Known Member
It takes 4200 Joules of energy to raise the temperature of 1 litre of water by 1 degree C.
Half a battery would give you 55 Amps for an hour, or 3600 seconds
55 A for 3600 seconds is 198000 joules
198000/4200 gives you a temperature rise of 47 degrees Centigrade for 1 litre of water.
So if you took 10 litres of water at 20C and heated it with 55A for an hour, it would be heated to 24.7C.
Heating water is expensive!
You have missed out the voltage. You calcs are out by a factor of 12 if we are talking about a 12 volt system
55A at 12volts = 660 watts
1 watt = 1 joule per second Therefore 660 watts for 1 hour = 660 x 3600 = 2376000 joules
...
The final result is that 55A at 12 volts for 1 hour will heat 10 litres through 56. 6 degrees, i.e. from 20C to 76.6C
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