Trojan battery output reducing incandescent bulb life

[cygnusv]

My 24 volt Trojan battery bank appears to be reducing bulb life. Output can be just over 29 volts when in conditioning mode. LED bulbs weren't lasting long so I went back to incandescent in a couple of places.

I would like to add a simple resistor or something into the few affected lights if it's possible. How would I go about it? If I could reduce the voltage at the bulbs by only 2 volts, I think it would help.

Any helpful ideas would be appreciated.

 

[Wing Mark]

It's easy to drop the 29V down to 24 using a 'low dropout regulator', a simple chip.
But when the input is only just over 24V, you'll lose a little power.
You could use a DC-DC converter and 12V bulbs, which tend to be more reliable.

 

[starfire]

3 diodes in series would drop approx 2.1V
Say 1N4001's

Depends on the led bulbs you use.
The ones I fit do 10-35V but not cheap replacements. Only had one fail out of several 100 fitted.

 

[Deleted member 36384]

I have a 24V Trojan Battery bank and a Sterling Pro Charge ultra, all 24V LED lighting. None have failed in about 3 years. Before that the incandescents had not failed either.

 

[PaulRainbow]

My 24 volt Trojan battery bank appears to be reducing bulb life. Output can be just over 29 volts when in conditioning mode. LED bulbs weren't lasting long so I went back to incandescent in a couple of places.

I would like to add a simple resistor or something into the few affected lights if it's possible. How would I go about it? If I could reduce the voltage at the bulbs by only 2 volts, I think it would help.

Any helpful ideas would be appreciated.

I have seen this before. A good solution would be a DC-DC converter. You can step the 2xV down to 24V, or down to 12V and use 12V LEDS, which seem more plentiful.

I would avoid using resistors. They are not an efficient way of doing it, plus, when the batteries are not on charge they will be giving a reduced voltage. The DC-DC converter will give a nice stable voltage.

 

[cygnusv]

I have seen this before. A good solution would be a DC-DC converter. You can step the 2xV down to 24V, or down to 12V and use 12V LEDS, which seem more plentiful.

I would avoid using resistors. They are not an efficient way of doing it, plus, when the batteries are not on charge they will be giving a reduced voltage. The DC-DC converter will give a nice stable voltage.

Thanks guys, I'll take a look at the DC/DC route ?