Buck Turgidson
Well-Known Member
Sounds like a big number, but:
F = 1/2 m v2 / s
Where s is the slow down distance of the impact (citation here: http://www.engineeringtoolbox.com/impact-force-d_1780.html)
So... rough and ready, but for an 80kg man (at least, he'll be wearing clothes, you'd hope!) falling across a foredeck (say an vertical actual height of 1m?) with a guardrail deflection of what, 20cm? Far enough to bend a stanchion but not snap it off or stop it working?
1/2 * 80 * 4.43^2 / 0.2 = 3924.98N
Now that number will obviously be spread across the tension in the guardwires and several stanchions, but it seems to me like if someone had a pretty big fall against one (certainly on your average size yacht) the chances are they'd crumple and absorb some of the impact. Certainly if someone fell hard against my stanchion I'd expect it to stay attached and the guardwires not to snap, but I'd be replacing it when I got home.
Wouldn't F = m g h / s be more appropriate?