#### Pandoramark1

##### New member

Evening All,

So after converting my old NAV light on my Pandora, to my special Home Made LED beauties total cost 90p a light , I found myself thinking I wonder what benefit I would get in terms of battery usage saving. So I tried some maths and came up with the following mess, like all good people I have shown my workings...

I have a 110Ah deep cycle battery.

After taking all electrical devices into consideration, Lights (NAV's and LED interior) clipper depth and a small compass light I am drawing 0.2A.

So if I have done this right I have worked out that my 110Ah battery will last for 6hrs based on a 90% depth of discharge and a 16.5A continuous draw

110Ah X 90% = 99Ah @ (6-hr rate)

99Ah / (6-hr rate) = 16.5 Amps

With a bit of luck at this point you are A) Still with me and B) I have not got it wrong so far.

So my question is what is the calculation that will let me find out how long it will take for me to reach a 90% Depth of Discharge based on a 0.2A continuous draw.

I hope this make sense, look forward to your responses and support

PMK1

So after converting my old NAV light on my Pandora, to my special Home Made LED beauties total cost 90p a light , I found myself thinking I wonder what benefit I would get in terms of battery usage saving. So I tried some maths and came up with the following mess, like all good people I have shown my workings...

I have a 110Ah deep cycle battery.

After taking all electrical devices into consideration, Lights (NAV's and LED interior) clipper depth and a small compass light I am drawing 0.2A.

So if I have done this right I have worked out that my 110Ah battery will last for 6hrs based on a 90% depth of discharge and a 16.5A continuous draw

110Ah X 90% = 99Ah @ (6-hr rate)

99Ah / (6-hr rate) = 16.5 Amps

With a bit of luck at this point you are A) Still with me and B) I have not got it wrong so far.

So my question is what is the calculation that will let me find out how long it will take for me to reach a 90% Depth of Discharge based on a 0.2A continuous draw.

I hope this make sense, look forward to your responses and support

PMK1

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