jim99
Well-Known Member
I am considering replacing my manual windlass with an electric. My understanding is that the usual benchmark for determining the minimum rated pull of a windlass I want is calculating three times the weight of anchor, chain, shackles, etc.
I rarely use rope, so it's 100 metres of 6mm G4 (200#), anchor (heaviest is 35#), shackles (maybe 10# tops if I also use a swivel). So that's 245# X 3 = 735# or 335kg. The total figure becomes 855# (390kg) if I double anchor.
That eliminates a lot of highly-rated small boat windlasses, especially considering I rarely use two anchors and almost never use 100 metres of chain.
Is there a better common sense way of arriving at the minimum pull that I need?
cheers
I rarely use rope, so it's 100 metres of 6mm G4 (200#), anchor (heaviest is 35#), shackles (maybe 10# tops if I also use a swivel). So that's 245# X 3 = 735# or 335kg. The total figure becomes 855# (390kg) if I double anchor.
That eliminates a lot of highly-rated small boat windlasses, especially considering I rarely use two anchors and almost never use 100 metres of chain.
Is there a better common sense way of arriving at the minimum pull that I need?
cheers