Sailingsaves
Well-Known Member
I looked at this website:
http://www.practicalcaravan.com/forum/equipment-accessories/39293-leisure-battery-testing-how
The chap concluded that a leisure battery that was fully charged used 18.4 Amps in 4 hours and left his battery at 75% discharged.
so 75% discharge took 18.4Amps
18.4Ah/75 = 0.245 (to obtain what 1% discharge represents)
(Or 18.4 divided by 75/100 = 18.4 x 100/75 = 0.245)
i.e. 1% of charged battery = 0.245A
so 0.245 x 100 (to get 100% charged capacity) = 24.5Ah.
NOW:
My second hand leisure AGM battery (rated 100Ah) used 1 Amp for 1 hour.
At rest the voltage was 12.85V
After 1 hour draw it rested at 12.81V
IFF (sic) I assume 12.88 is fully charged (instead of 12.7 Volt), then is the following correct?
12.85V to 12.81 Volt = 5% discharge.
So 5% discharge took 1Amp.
1 divided by 5/100 = 1 x 100/5 = 20
i.e. 1% of charged battery = 20A
so 20 x 100 (to get 100% charged capacity) = 200Ah CLEARLY WRONG !!!!!
or, at should it be
1 divided by 5 = 0.2
0.2 x 100=20Ah total capacity ?!
Anyone help?
IN SUMMARY, I took a battery rested at 12.85V for 24 hours. Drew 1 Amp for 1 hours and after 2 hours of rest, battery returned to 12.81V - what capacity does this 10year old battery have now?
Thanks if anyone an cure my headache.
Cheers in advance.
For info, one website I have lost location of stated:
12.7V = 100% charged
12.64V = 95% charged
12.58V = 90% charged
etc
http://www.practicalcaravan.com/forum/equipment-accessories/39293-leisure-battery-testing-how
The chap concluded that a leisure battery that was fully charged used 18.4 Amps in 4 hours and left his battery at 75% discharged.
so 75% discharge took 18.4Amps
18.4Ah/75 = 0.245 (to obtain what 1% discharge represents)
(Or 18.4 divided by 75/100 = 18.4 x 100/75 = 0.245)
i.e. 1% of charged battery = 0.245A
so 0.245 x 100 (to get 100% charged capacity) = 24.5Ah.
NOW:
My second hand leisure AGM battery (rated 100Ah) used 1 Amp for 1 hour.
At rest the voltage was 12.85V
After 1 hour draw it rested at 12.81V
IFF (sic) I assume 12.88 is fully charged (instead of 12.7 Volt), then is the following correct?
12.85V to 12.81 Volt = 5% discharge.
So 5% discharge took 1Amp.
1 divided by 5/100 = 1 x 100/5 = 20
i.e. 1% of charged battery = 20A
so 20 x 100 (to get 100% charged capacity) = 200Ah CLEARLY WRONG !!!!!
or, at should it be
1 divided by 5 = 0.2
0.2 x 100=20Ah total capacity ?!
Anyone help?
IN SUMMARY, I took a battery rested at 12.85V for 24 hours. Drew 1 Amp for 1 hours and after 2 hours of rest, battery returned to 12.81V - what capacity does this 10year old battery have now?
Thanks if anyone an cure my headache.
Cheers in advance.
For info, one website I have lost location of stated:
12.7V = 100% charged
12.64V = 95% charged
12.58V = 90% charged
etc